# Maths - 2 Dimentional Vector Geometry

## Abstract

This page is about how vectors can represent objects in two dimensions and some useful concepts for analysing 2D geometry.

This page assumes an understanding of coordinate systems described here, you may also want to review angles .

## Points and Lines from the Origin

We can use a 2 dimensional vector to represent a displacement from the origin and therefore specify a given point by showing its displacement from the origin. For instance, the point shown below is 5 up and 9 right, which can be represented by the vector (9,5). By convention the x coordinate is shown first, then the y coordinate. ## Angles

In two dimensions angles are scalar quantities. If we have two 2D vectors (V1 and V2) then we could work out the angle between them, at the origin, by using:

angle = acos(v1•v2)

or

angle = atan2(v2.y,v2.x) - atan2(v1.y,v1.x)

depending on whether we want to make the angle negative if V1 and V2 are swapped over. This is more fully explained on this page.

The first version uses the vector dot product '•' which generates a scalar from two vectors as explained here. The second version uses the x and y components of the vectors.

If we want to work out an angle at a point other than the origin, then we can translate the point to the origin by subtracting the displacement from all the vectors.

## Areas

In two dimensions areas are scalar quantities. An area can be represented by one number, this does not say anything about the shape of the two dimensional object just the amount of 'surface' it contains. Any two dimensional closed shape encloses an area, this might be a simple shape like a rectangle or a circle or it could be a very complex shape. In any case its area is a single scalar number.

As an example let us take the area enclosed by two vectors as shown in yellow in the diagram above, this area is given by:

area = V1x * V2.y - V1y * V2.x

As can be shown by the following construction (Thank you very much to jeandavid54 for telling me about this construction)  1) We can see that the area = V1x * V2.y - V1y * V2.x is equal to the green area in the diagram above. 2) If we move the brown cutout up, the green area remains the same.  3) If we cutout the green areas which are outside the boundary of the two vectors, in the way shown above, then we can move them inside. 4) Now the green are which we know is equal to: V1x * V2.y - V1y * V2.x fits exactly in the area bounded by the two vectors.

## Where next

These topics can be extended to three dimensions as discussed here.

To generalise further we can get more insight by looking at these same topics in terms of Clifford Algebra and Geometric Algebra as discussed here.